1.0.0[−][src]Trait nom::lib::std::borrow::BorrowMut
A trait for mutably borrowing data.
As a companion to Borrow<T> this trait allows a type to borrow as
an underlying type by providing a mutable reference. See Borrow<T>
for more information on borrowing as another type.
Required methods
fn borrow_mut(&mut self) -> &mut Borrowedⓘ
Mutably borrows from an owned value.
Examples
use std::borrow::BorrowMut; fn check<T: BorrowMut<[i32]>>(mut v: T) { assert_eq!(&mut [1, 2, 3], v.borrow_mut()); } let v = vec![1, 2, 3]; check(v);
Implementations on Foreign Types
impl<T, const N: usize> BorrowMut<[T]> for [T; N][src]
fn borrow_mut(&mut self) -> &mut [T]ⓘ[src]
impl<'_, T> BorrowMut<T> for &'_ mut T where
T: ?Sized, [src]
T: ?Sized,
fn borrow_mut(&mut self) -> &mut Tⓘ[src]
impl<A> BorrowMut<[<A as Array>::Item]> for ArrayVec<A> where
A: Array, [src]
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A: Array,
Implementors
impl BorrowMut<str> for String[src]
fn borrow_mut(&mut self) -> &mut str[src]
impl<T> BorrowMut<[T]> for Vec<T>[src]
fn borrow_mut(&mut self) -> &mut [T]ⓘ[src]
impl<T> BorrowMut<T> for Box<T> where
T: ?Sized, [src]
T: ?Sized,
fn borrow_mut(&mut self) -> &mut Tⓘ[src]
impl<T> BorrowMut<T> for T where
T: ?Sized, [src]
T: ?Sized,